(lispref.info)Void Variables

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When a Variable is "Void"

   If you have never given a symbol any value as a global variable, we
say that that symbol's global value is "void".  In other words, the
symbol's value cell does not have any Lisp object in it.  If you try to
evaluate the symbol, you get a `void-variable' error rather than a

   Note that a value of `nil' is not the same as void.  The symbol
`nil' is a Lisp object and can be the value of a variable just as any
other object can be; but it is *a value*.  A void variable does not
have any value.

   After you have given a variable a value, you can make it void once
more using `makunbound'.

 - Function: makunbound SYMBOL
     This function makes the current binding of SYMBOL void.  This
     causes any future attempt to use this symbol as a variable to
     signal the error `void-variable', unless or until you set it again.

     `makunbound' returns SYMBOL.

          (makunbound 'x)      ; Make the global value
                               ;   of `x' void.
               => x
          error--> Symbol's value as variable is void: x

     If SYMBOL is locally bound, `makunbound' affects the most local
     existing binding.  This is the only way a symbol can have a void
     local binding, since all the constructs that create local bindings
     create them with values.  In this case, the voidness lasts at most
     as long as the binding does; when the binding is removed due to
     exit from the construct that made it, the previous or global
     binding is reexposed as usual, and the variable is no longer void
     unless the newly reexposed binding was void all along.

          (setq x 1)               ; Put a value in the global binding.
               => 1
          (let ((x 2))             ; Locally bind it.
            (makunbound 'x)        ; Void the local binding.
          error--> Symbol's value as variable is void: x

          x                        ; The global binding is unchanged.
               => 1
          (let ((x 2))             ; Locally bind it.
            (let ((x 3))           ; And again.
              (makunbound 'x)      ; Void the innermost-local binding.
              x))                  ; And refer: it's void.
          error--> Symbol's value as variable is void: x

          (let ((x 2))
            (let ((x 3))
              (makunbound 'x))     ; Void inner binding, then remove it.
            x)                     ; Now outer `let' binding is visible.
               => 2

   A variable that has been made void with `makunbound' is
indistinguishable from one that has never received a value and has
always been void.

   You can use the function `boundp' to test whether a variable is
currently void.

 - Function: boundp VARIABLE
     `boundp' returns `t' if VARIABLE (a symbol) is not void; more
     precisely, if its current binding is not void.  It returns `nil'

          (boundp 'abracadabra)          ; Starts out void.
               => nil

          (let ((abracadabra 5))         ; Locally bind it.
            (boundp 'abracadabra))
               => t

          (boundp 'abracadabra)          ; Still globally void.
               => nil

          (setq abracadabra 5)           ; Make it globally nonvoid.
               => 5

          (boundp 'abracadabra)
               => t

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